Dos for loop with delay

Command below performing 1000 iterations printing number with 1 second delay interval

for /l %i in (1,1,1000) do timeout /t 1 > nul| echo %i

Additional refer:
https://hubpages.com/technology/How-to-Make-A-Windows-Batch-File-Loop-Sleep-or-Delay-For-Specific-Interval-of-Time